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Mj Kwh
HELPPP physical electricity .:(:(:(:(? test tomorrow
physics of electricity, if helppp please? 1.A model bill for electricity is $ 70 for a month. How much energy is used in kW'h? I have 0.1 kWh do not know if its right 2. Type nuclear power plant has a capacity of 1.0 GW (10 ^ 9 watts). If all the energy produced in an operation the day how many plants were sold to win? I have 2,400,000 x 10 ^ 7 3) Tell the calculator 0.20 mA required to operate and will be 2.0 minutes to solve this problem. How much support will be paid during this period? I have 2.4 x 10 ^ -2 u can teach me how do if I have bad ... please and thank you very much details electric utilities pay 5.0cent/MJ
1) It is not fair. It is highly unlikely that the electricity consumption would be nearly a month. Just to get an idea 1 kWh is the energy consumed by an electrical fire in a bar (1 kW) in an hour! Let's see what the response is correct. If you pay 5 cents / MJ so if you pay $ 70 (unless the power company is cheating, it is very possible), which used 70/0.05 = 1400 MJ electricity. So what is in kWh? Good 1 kW / h of energy used in a ratio of 1 kilowatt for 1 hour. Now 1 watt is 1 J / s. So 1 kW is 1000 W / s. From 1h is 60 * 60 = 3600 seconds, you get 1 kw = 1000 * h * s J / J = 3600 = 3.6 million So, MJ 3.6 MJ = 1400 1400 / 3,6 = 389 kWh (the nearest kWh) - 2) 10 ^ 9 watts for one day (= 24) gives a power of 24 x 10 ^ 9 Wh. Dividing by 1000 that is 24 x 10 ^ 6 kWh. If they get $ 0.05 per kWh, the plant gained 0.05 x 24 x 10 ^ 6, $ 1.2 million per day - 3) You know that 1A = 1C / s The total amount of fees that will use 0.02 * 2 * 60 = 2.4 coulombs C - Good luck with the exam tomorrow!
まんのう町議会 22年12月本議会 一般質問
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Days of Atonement $1.90 ... |
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